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Appendix B
To obtain Eq.(
\begin{align} H = \frac{\dot{S}}{\ddot{S}}, \space H_0 = \frac{\dot{S_0}}{\ddot{S_0}}, \space \rho_c = \frac{3H^2}{8 \pi G}, \space \rho_{c,0} = \frac{3H_0^2}{8 \pi G}, \space \rho S^3 = \rho_0 S^3_0 \nonumber \end{align}
From the first Friedmann equation,
\begin{align} \dot{S}^2 - \frac{8}{3} \pi G \rho S^2 & = \dot{S}_0^2 - \frac{8}{3} \ pi G \rho_0 S^2_0 \nonumber \\ \dot{S}^2 & = \dot{S}_0^2 \left( 1 - \frac{8}{3} \pi G \rho_0 \frac{S_0^2}{\dot{S}^2} + \frac{8}{3} \pi G \rho \frac{S^2}{\dot{S}_0^2 } \right) \nonumber \\ & = \dot{S}_0^2 \left ( 1-\frac{H_0^2}{\rho_{c,0}}\rho\frac{S_0^2}{\dot{S}_0^2} + \frac{H_0^2}{\rho_{c,0}}\rho_0\frac{S_0^3}{S^3} \frac{S^2}{\dot{S}_0^2} \right) \nonumber \\ & = \dot{S}_0^2 \left ( 1-\frac{1}{\rho_{c,0}}\rho + \frac{1}{\rho_{c,0}}\rho_0\frac{S_0}{S} \right) \nonumber \\ & = \dot{S}_0^2 \left ( 1+\frac{\rho_0}{\rho_{c,0}} \left( \frac{1}{x} -1 \right) \right) \nonumber \\ \end{align}
where x=\frac{S}{S_0}.
\begin{align} H_0t_0 &= H_0 \int_0^{t_0} {dt} \nonumber \\ &= H_0 \int_0^{S_0} {\frac{dt}{dS} dS} \nonumber \\ &= H_0 \int_0^{1} { (\dot{S})^{-1} S_0 \space dx} \nonumber \\ &= H_0 \int_0^{1} { \dot{S}_0^{-1} \left ( 1+\frac{\rho_0}{\rho_{c,0}} \left( \frac{1}{x} -1 \right) \right)^{-\frac{1}{2}} S_0 \space dx} \nonumber \\ &= \int_0^{1} { \left ( 1+\frac{\rho_0}{\rho_{c,0}} \left( \frac{1}{x} -1 \right)\right)^{-\frac{1}{2}} dx} \nonumber \\ \end{align}